[solved] Get the result of SendMessage

[Bicou]

Hello again!
This time I'm trying to communicate with winamp, using windows messages: I'd like to get the shuffle status, for example.
Here's what Winamp SDK gives:

Code: Select all

#define WM_WA_IPC WM_USER
// [...]

/* (requires Winamp 2.4+)
** val=SendMessage(hwnd_winamp,WM_WA_IPC,0,IPC_GET_SHUFFLE);
**
** IPC_GET_SHUFFLE returns the status of the Shuffle option (1 if set)
*/

In Windows SDK I have #define WM_USER 0x0400 so I guess I should send windows message 1024 (since 0x0400h = 1024d), with 0 as wParam and 250 as lParam.

Here's my macro:
1. SendMessage( 1024, 0, 250 )
2. OSD : {eg.result}

It shows none, but I think it's normal since I did not tell EG to which window handle I want to send the message... I tried to put a Find Window: winamp.exe macro just before the Send Message macro, but it sill does not work.

What's the problem?

Thanks

[Bitmonster]

The SendMessage action does not return any value. Since the message might be send to a list of windows, it wouldn't make much sense.

You can try it with a PythonScript:

Code: Select all

import win32gui

hWinamp = win32gui.FindWindow('Winamp v1.x', None)
eg.result = win32gui.SendMessage(hWinamp, 1024, 0, 250)

[Bicou]

This is great, thanks again for your help.